Math, asked by miracle9392, 9 months ago

The length of a rectangle field is a greater than twice its breadth by 10 m. Its diagonal is 5m more than its length. Find the area of the field

Answers

Answered by TheLightningWizard
5

Answer:

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Step-by-step explanation:

GIVEN -

SHAPE - RECTANGLE

LENGTH IT IS GREATER THAN TWICE OF BREATH BY 10 M

DIAGONAL IS 5 MORE THAN LENGTH

MYSTERY TOPIC -

WHAT IS THE AREA OF THE FIELD

let breath is equal to x

so the length will be 2 x + 10

and the same as diagonal will be ( 2 x + 10) + 5

DIAGONAL OF RECTANGLE = LENGTH SQUARE + BREATH SQUARE

(2x + 10) + 5 =   \sqrt{ {x}^{2} ( +2x + 10)}

 {((2x + 10) + 5)}^{2}  =   {x}^{2}  +  {(2x + 10) }^{2}

( {4x}^{2}  + 100) + 25 =  {x}^{2}  +  {4x}^{2}  + 100

 {4x}^{2}  + 25 + 125 =  {x}^{2}  +  {4x}^{2}  + 100

50 =  {x}^{2}

 x =  \sqrt{50}

now now we have the value of x and we can use it to find other values.

breath = 250+10

diagonal = 250+10+5

✌️____THANKS____✌️

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