Question

The length of a rectangle is 1 cm more than twice its breadth .



The perimeter of the rectangle is 50 cm . then find length and breadth​

Answer 1

Answer:

Step-by-step explanation:

let the breadth of the rectangle be b

length= 2b+1

perimeter= 2(l+b)

Substituting the value of length

p= 2(2b+1+ b)

50= 2(3b+1)

50/2= (3b+1)

25= 3b+1

25-1= 3b

b= 24/3= 8

breadth = 8cm

length = 2(8) + 1= 17cm

Answer 2

Answer:

let the breadth of rectangle be (x)

now according to given condition

length (L) = 1+ 2x

perimeter = 50 cm

perimeter = 2(l+b)

50 = 2( 1+2x +x)

50= 2(1+3x)

50/2= 1+3x

25-1= 3x

24= 3x

x= 8cm

value of length= 1+2x

1+2(8)

17 cm

value of breadth =8cm