Question

The length of a rectangle is 10 cm and its perimeter is equal to that of a square of
side 9 cm. Find the area of the rectangle.
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Answer 1

Answer:

A=90cm²

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Answer 2

Answer:

Answer

{80cm}^{2}80cm2

Given .

The length of a rectangle is 10 cm.and a square of side 9 cm.

Find

Area of the Rectangle ?

Solution

Perimeter of square = 4 × side .

4 × 9cm

36cm.

Now According to questions

Perimeter of rectangle = perimeter of square.

here the length of rectangle is 10 cm .and breadth is b.

2 ( l + b ) = 4 × Side

2( 10 + b ) = 4 × 9cm

20 + 2b = 36cm

2b = 36 - 20

2b = 16 cm

\begin{gathered}b \: = \frac{16}{2} \\ \\ = 8\end{gathered}b=216=8

Again here we find Area of rectangle.

Area of rectangle = length × breadth.

10 cm × 8cm.

{80cm}^{2}80cm2

Therefore the area of rectangle is equal to

{80cm}^{2}80cm2

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Step-by-step explanation:

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