Question

The length of a rectangle is 10 m more than its breadth. if the perimeter of rectangle is 80 m, find the dimensions of the rectangle.

Answer 1

x length
y breadth
x=y+10.

perimeter 80=2x%2B2y
2%28y%2B10%29%2B2y=80
y%2B10%2By=40
2y%2B10=40
2y=30
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y=15 which means x=25
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Answer 2

Hello..........^_^

Here is your answer...

Given :- The length of the rectangle is 10m more than it's breadth.
Perimeter of rectangle is 80m.

Let the breadth be ' x m'
so length = (x+10)m
$Perimeter \: \: of \: \: rectangle = 2 (length X breadth) \\ \\ = > 80 = 2((x + 10) + x) \\ \\ = > \frac{80}{2} = 2x + 10 \\ \\ = > 40 = 2x + 10 \\ \\ = > 40 - 10 = 2x \\ \\ = > 30 = 2x \\ \\ = > \frac{30}{2} = x \\ \\ = > 15 = x$

breadth = x m = 15m
length = (x+10)m = 15 + 10 = 25m


CHECK
perimeter of rectangle
= 2(length + breadth) m
= 2(15+ 25) m
= 2 X 40 m
= 80m



Hope it helps......... ^_^