Question

the length of a rectangle is 12 centimetre and each of its diagonal measures 15 cm find its breadth​

Answer 1

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Answer 2

Answer:

The Breadth of the rectangle is 9 cm.

Step-by-step explanation:

Given :

Length of the rectangle = 12 cm

Diagonal measures = 15 cm

To find :

Breadth = ??

Solution :

Solving According to Pythagoras theorem :

In ∆ ADC -

• Hypotenuse = 15 cm
• Base = 12 cm
• Height = x

$\bigstar \: {\boxed{\sf{(Hypotenuse)^{2} = (Base)^{2} + (Height)^{2} }}}$

$\sf{\implies} \: {15}^{2} = {12}^{2} + {x}^{2} \\ \\ \sf{\implies} \:225 = 144 + {x}^{2} \\ \\ \sf{\implies} \: {x}^{2} = 225 - 144 \\ \\ \sf{\implies} \: {x}^{2} = 81 \\ \\ \sf{\implies} \:x = \sqrt{81} \\ \\ \sf{\implies} \:x = 9$

Height = 9 cm

$\therefore$ The Breadth of the rectangle is 9 cm.