Question

The length of a rectangle is 12 CM and the length of its diagonal is 15 CM. The area of the rectangle is ​

Answer 1

Given :

Length of the rectangle = 12 cm

Length of each of its diagonal = 15 cm

$\sf{\implies Diagonal = \sqrt{(Length)^2 + (Breadth)^2}}$

$\sf{\implies 15 = \sqrt{(12)^2 + (Breadth)^2}}$

Squaring both the sides, we get.

$\sf{\implies 15^2 = 12^2+ Breadth^2}$

$\sf{\implies 225 - 144 = Breadth^2}$

$\sf{\implies Breadth^2 = 81}$

$\sf{\implies Breadth = \sqrt{81}}$

$\underline{ \boxed{ \sf{ \orange{Breadth = 9 cm}}}}$

Answer 2

Answer :-

• Area of Rectangle = 108 sq. cm.

Explanation :-

Given :

• Length of the rectangle = 12 cm.

• Diagonal of the rectangle = 15 cm.

To find :

• Area of Rectangle.

Solution :

First, Let's Calculate the Breadth.

We know that,

(Diagonal)² = (Length)² + (Breadth)²

➞ 15² = 12² + Breadth²

➞ 225 = 144 + Breadth²

➞ Breadth² = 225 - 144.

➞ Breadth² = 81.

➞ Breadth² = 9²

➞ Breadth = 9 cm.

Now, Let's Calculate Area.

We know that,

Area of Rectangle = l × b.

➞ Area = 12 × 9 cm²

➞ Area = 108 cm²

Therefore, Area of Rectangle = 108 sq. cm.