The length of a rectangle is 12 m more than twice the width. The area of the rectangle is 320 square m. Write an equation that can be used to find the length and width of the rectangle. Also find the dimensions of the rectangle.
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let
width = x m
length=(2x+12)m
area of the rectangle=320 square m
length× width=320
(2x+12)×x=320
2*(x+6)x=320
x(x+6)=160
x^2+6x-160=0
x^2-10x+16x-160=0
x(x-10)+16(x-10)=0
(x-10)(x+16)=0
x-10=0 or x+16=0
x=10 or x= -16
x should be positive value
x=10
therefore
width=x=10m
length=2x+12
=2×10+12
=20 + 12
= 32m
I hope this helps you.
width = x m
length=(2x+12)m
area of the rectangle=320 square m
length× width=320
(2x+12)×x=320
2*(x+6)x=320
x(x+6)=160
x^2+6x-160=0
x^2-10x+16x-160=0
x(x-10)+16(x-10)=0
(x-10)(x+16)=0
x-10=0 or x+16=0
x=10 or x= -16
x should be positive value
x=10
therefore
width=x=10m
length=2x+12
=2×10+12
=20 + 12
= 32m
I hope this helps you.
SunilamYamini:
in the end there is a mistake, it should be 2x10+12
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