Question

the length of a rectangle is 15 cm greater than its breadth its perimeter is 150 cm find the dimension of the rectangle.​

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Length is 45 cm and Breadth is 30 m.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

Perimeter of Rectangle = 150 cm

Length of the Rectangle = 15 cm more than Breadth

To find :

The dimensions of the Rectangle

Solution :

Consider the Breadth as x

Consider the Length as x + 15

★ $\boxed{\sf{Perimeter=2(Length+Breadth)}}$

$\sf{\implies} \: 2(x + x + 15) = 150$

$\sf{\implies} \:2x + 2x + 30 = 150$

$\sf{\implies} \:4x + 30 = 150$

$\sf{\implies} \:4x = 150 - 30$

$\sf{\implies} \:4x = 120$

$\sf{\implies} \:x = \dfrac{120}{4}$

$\sf{\implies} \:x = 30$

$\rule{300}{1.5}$

★ Value of x + 15

$\sf{\implies} \:30 + 15$

$\sf{\implies} \:45$

$\therefore$ The Length is 45 cm and Breadth is 30 m.

$\rule{300}{1.5}$

$\mathfrak{\large{\underline{\underline{Verification :- }}}}$

$\sf{\implies} \: 2(30+ 30+ 15) = 150$

$\sf{\implies} \: 60+ 60 + 30= 150$

$\sf{\implies} \: 120+ 30= 150$

$\sf{\implies} \:150= 150$

$\therefore$ The Length is 45 cm and Breadth is 30 m.

Answer 2

GIVEN :

Length of a Rectangle is 15cm greater than its breadth.

Let the breadth of Rectangle be x

Length of the Rectangle = x + 15

Perimeter of Rectangle = 2[ l + b ] = 150

According to the problem,

2[ l + b ] = 150

2[ x + x + 15 ] = 150

2x + 15 = 150/2

2x + 15 = 75

2x = 75 - 15

2x = 60

x = 60/2

x = 30

Breadth = x = 30

Then,

Length = x + 15 = 30 + 15 = 45

Therefore, the length and breadth of Rectangle are 45 and 30 respectively.