Question

10. Two similarly and equally charged identical metal
spheres A and B repel each other with a force of
2.0 × 10-N. A third identical, uncharged sphere C
is touched with A and then placed at the mid-point
between A and B. What is net electric force on C?
Ans. 2.0 x 10-5 N, towards A.​

Answer 1

Answer:

2.0 x 10-5 N,

Explanation:

A , B and C three identical charges given in such a way that force between A and B is F = 2 × 10⁻⁵ N . let charge on each ( A and B sphere) is q.

e.g., F = kq²/r²

Now, a third charge C sphere touched with A

Then, charge q sharing with A and C equally .

So, charge on C = q/2 and charge on A = q/2

Now, charge C is placed between A and B

So, net force act on C = force due to B - force due to A [ here negative sign is used because both the forces are repulsive and hence , net force is the difference of those forces]

e.g.,net force on

C = K(q/2)(q)/(r/2)² - K(q/2)(q/2)/(r/2)²

=2 Kq²/r² - Kq²/r²

= Kq²/r²

= F = 2 × 10⁻⁵ N

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Answer 2

Explanation:

Direction of net force is in left side.

Net force is equal to :

= K Q^2 / X^2 in direction of A

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