Question

The length of a rectangle is 15 m more than twice the width. The area of the rectangle is 320 spuare meter. Write an equation that can be used to find the lenght and width of the rectangle. Also find the dimension of the rectangle.
need a correct verified answer​

Answer 1

Answer:

let the width be b m

so acc to question, length = 2(12+b) m

area = 320 sqm

Step-by-step explanation:

now, area of rect. -l'b

320 = b (24+2b)

320=24b + 2b^2

solving the equation by quadratic formula.

b=16 or b= -40

since breadth cant be negative, b= -40 is rejected so width = 16m

and accordingly length = 2(12+16) = 2*28= 54m so the equation is 320=24b +2b^2

and dimensions are breadth = 16m and length = 54m HOPE IT HELPS :D

Answer 2

Answer:

let the width of the rectangle is x m

then length =(2x+15) m

so,the equation is

x(2x+15)=320

=> 2x^2+15x-320=0