Question

The length of a rectangle is 19 cm more than it's breadth. If the perimeter of the rectangle is 138 cm, find it's length and breadth.​

Answer 1

Answer:

Given :-

• Length of rectangle is 19 cm more than breadth
• Perimeter = 138 cm

To Find :-

• Length and Breadth

Solution :-

As we know that

${\textsf {\textbf{\blue{Perimeter = 2(l + b)}}}}$

• Let the breadth be x
• And length = (x + 19)

$\sf \: 138 = 2 \bigg((x + 19) + x \bigg)$

$\sf \: 138 = 2(x + 19 + x)$

$\sf \dfrac{138}2 = x + 1 9 + x$

$\sf \: 69 = x + 19 + x$

$\sf \: 69 = 2x + 19$

$\sf \: 69 - 19 = 2x$

$\sf \: 50 = 2x$

$\sf \: x \: = \dfrac{50}{2}$

$\sf \: x \: = 25$

Therefore :-

Breadth = 25 cm

Length = 25 + 19 = 44 cm

Kñow More :–

• Area of rectangle = Length × Breadth
• Diagonal of square = $\sqrt{2}$ × side

Answer 2

Answer :

• Length = 44cm
• Breadth = 25cm

Given :

• Length of a rectangle is 19cm more than its breadth.
• Perimeter of rectangle is 138cm

To find :

• length and breadth

Solution:

• Let the breadth of rectangle be xcm
• Length of rectangle be (x+19)

Given perimeter of rectangle is 138cm

As we know that ,

• perimeter of rectangle is 2(l + b)

where,

• l is length (x + 19)
• b is xcm
• perimeter of rectangle is 138cm

➵ Perimeter of rectangle =2(l + b)

➵ 2(length +breadth) = 138

where , length is x + 19 , breadth is x

➵ 2(x + 19 + x) = 138

➵ (x + 19 + x) = 138/2

➵ (x + 19 + x) = 69

➵ 2x = 69 - 19

➵ 2x = 50

➵ x = 50/2

➵ x = 25cm

Breadth is x = 25cm

Then,

• length = (x+19) = (25+19) = 44cm
• breadth = x = 25cm

More Explanation :

• perimeter of rectangle (p) = 2(l + b)
• Area of rectangle (A) = lb
• Diagonal of rectangle (D) = √l² + b²
• Where , l is length , b is breadth