the length of a rectangle is 2 cm more than thrice its breadth if its perimeter is 68 cm find the length of the rectangle
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let the length be x & breadth be y
according to first condition,
x=3y+2
P=68cm.
P =2 (l+b)
P=2 (x+y)
P=2 (3y+2+y)
P=2 (4y+2)
68=8y+4
68-4=8y
64=8y
y=64/8
y=8
x=3y+2
=3 (8)+2
=24+2
=26cm.
The length of the rectangle is 26cm
according to first condition,
x=3y+2
P=68cm.
P =2 (l+b)
P=2 (x+y)
P=2 (3y+2+y)
P=2 (4y+2)
68=8y+4
68-4=8y
64=8y
y=64/8
y=8
x=3y+2
=3 (8)+2
=24+2
=26cm.
The length of the rectangle is 26cm
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