Question

- The length of a rectangle is 20 cm more than its breadth. If the perimeter is 100 cm find
the dimension of the rectangle.

​

Answer 1

⠀⠀⠀☯ Let's consider that the Breadth of the rectangle be b.

Given that,

• The length of a rectangle is 20 cm more than its breadth.

Therefore,

$:\implies\sf Breadth = (b + 20) cm$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀

⠀⠀⠀⠀$\dag\;{\underline{\frak{As \; we \; know \: that}}}$

⠀⠀⠀⠀

$\star\:\boxed{\sf{\pink{Perimeter_{\:(Rectangle)} = 2(Length + Breadth)}}}$

Given that,

• Perimeter of the rectangle is 100 cm.
• And, Length is (b + 20) cm.

⠀⠀⠀⠀

$:\implies\sf 2(Length + Breadth) = 100 \\\\\\:\implies\sf 2(b + 20 + b) = 100 \\\\\\:\implies\sf 2b + 20 = \cancel\dfrac{100}{2} \\\\\\:\implies\sf 2b + 20 = 50 \\\\\\:\implies\sf 2b = 50 - 20 \\\\\\:\implies\sf 2b = 30 \\\\\\:\implies\sf b = \cancel\dfrac{30}{2} \\\\\\:\implies{\underline{\boxed{\frak{\purple{b = 15 \; cm}}}}}\:\bigstar$

⠀⠀⠀⠀

Hence,

⠀⠀⠀⠀

• Breadth of the rectangle (b) = 15 cm
• Length of the rectangle (b + 20), (15 + 20) = 35 cm.

⠀⠀⠀⠀

$\therefore\:{\underline{\sf{Hence, \ Dimensions\: of \ the \ rectangle \ are \ {\textsf{\textbf{15 and 35 cm}}}.}}}$

Answer 2

Answer:

$\purple{ \bigstar}{ \underline \purple{question : - }}$

The length of a rectangle is 20 cm more than its breadth. If the perimeter is 100 cm find

the dimension of the rectangle.

Let

• Let us assume that breadth be "b"

Step-by-step explanation:

$\pink{ \bigstar}{ \underline \orange{condition: - }}$

• Length of the rectangle is 20 cm more than it's breadth

•°• The breadth in equation form :-

$: \: \: = > \: breadth \: = \: (b + 20)cm$

Formula to be used

$\red{ \bigstar}perimeter \: of \: a \: rectangle = { \frak{ \underline \purple{2(length \: + breadth)}}}$

Given

• Perimeter of the rectangle given :- 100 cm
• Length (l) is (breadth + 20 ) cm

Now,

Let's solve Your equation step-by-step

=》2 (Length + breadth) = 100

=》2 ({b+20} + b) = 100

$= > \: 2b + 20 = \frac{100}{2}$

=》 2b + 20 = 50

=》2b = 50 - 20

=》2b = 30

$= > b = \frac{30}{2}$

=》b = 15

•°• Breadth of the rectangle (b) = 15 cm

•°• Length of the rectangle , (b+20) = (15+20) = 35 cm

Hence the dimension becomes 15 cm and 35 cm