Question

The length of a rectangle is
20%. more than its breadth. what
will be the ratio of the area of a
rectangle to that of a square
whose side is equal to the
breadth of the rectangle?​

Answer 1

þrð¢ê§§

Lê† †hê breadth of the rectangle is =b unit

therefore the length=120x/100=6x/5

$now \: area \: = x \times \frac{6x}{5} = \frac{6x {}^{2} }{5} unit {}^{2} \\ \\ the \: side \: of \: the \: square \: having \: its \: side \: equal \: to \: the \: breadth \: of \: the \: rectangle \: is \: = x \: unit \\ its \: area = x {}^{2} unit {}^{2} \\ therefore \: the \: ratio \: between \: the \: area \: of \: rectangle \: to \: the \: area \: of \: square \\ = \frac{ \frac{6x {}^{2} }{5} }{x {}^{2} } \\ = \frac{6}{5} \\ = 6:5$

Answer 2

Step-by-step explanation:

Refer to the attachment please ✌️