Question

the length of a rectangle is 25 cm and its area is 325 sq cm find it's breadth class 9​

Answer 1

☘️ Given :

• Area of the rectangle = 325 sq cm
• length of the rectangle = 25 cm
• We have to find breadth

☘️ Solution :

Are of rectangle = l × b

→ 325 cm² = 25 × b

→ breadth = 325/25

→ breadth = 13 cm

Therefore, the breadth of the rectangle = 13 cm.

☘️ Verification :

Are of rectangle = l × b

→ 325 = 25 × 13

→ 325 = 325

→ .°. LHS = RHS

Hence, verified.

Answer 2

Answer:

$\underline{\underline{\bigstar{\textbf{\textsf{\green{\: Given\::-}}}}}}$

• Lenght of Rectangle = 25 cm
• Area of Rectangle = 325 cm²

$\begin{gathered}\end{gathered}$

$\underline{\underline{\bigstar{\textbf{\textsf{\green{\: To Find\::-}}}}}}$

• Breadth of Rectangle

$\begin{gathered}\end{gathered}$

$\underline{\underline{\bigstar{\textbf{\textsf{\green{\: Using Formula\::-}}}}}}$

$\quad\dag{\underline{\boxed{\sf{Area \: of \: Rectangle = Lenght \times Breadth}}}}$

$\begin{gathered}\end{gathered}$

$\underline{\underline{\bigstar{\textbf{\textsf{\green{\: Diagram\::-}}}}}}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large25 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large13 cm}\put(-0.5,-0.4){\bf}\put(-0.5,3.2){\bf}\put(5.3,-0.4){\bf}\put(5.3,3.2){\bf}\end{picture}$

$\begin{gathered}\end{gathered}$

$\underline{\underline{\bigstar{\textbf{\textsf{\green{\: Solution\::-}}}}}}$

$\red\bigstar$ Finding the breadth of rectangle :-

$\quad{\dashrightarrow{\sf{Area \: of \: Rectangle = Lenght \times Breadth}}}$

• Substuting the values

$\quad{\dashrightarrow{\sf{325 =25\times Breadth}}}$

$\quad{\dashrightarrow{\sf{Breadth = \dfrac{325}{25} }}}$

$\quad{\dashrightarrow{\sf{Breadth = \cancel\dfrac{325}{25} }}}$

$\quad{\dashrightarrow{\sf{Breadth = 13 \: cm}}}$

$\quad\bigstar{\underline{\boxed{\sf{\purple{Breadth = 13 \: cm}}}}}$

∴ The breadth of rectangle is 13 cm.

$\begin{gathered}\end{gathered}$

$\underline{\underline{\bigstar{\textbf{\textsf{\:Verification\::-}}}}}$

$\red\bigstar$ Checking our answer :-

$\quad{\dashrightarrow{\sf{Area \: of \: Rectangle = Lenght \times Breadth}}}$

• Substuting the values

$\quad{\dashrightarrow{\sf{325 \: {cm}^{2} = 25 \times 13}}}$

$\quad{\dashrightarrow{\sf{325 \: {cm}^{2} = 325\: {cm}^{2} }}}$

$\quad\bigstar{\underline{\boxed{\sf{\purple{LHS = RHS}}}}}$

∴ Hence Verified!

$\begin{gathered}\end{gathered}$

$\underline{\underline{\bigstar{\textbf{\textsf{\green{\: Request\::-}}}}}}$

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$\begin{gathered}\end{gathered}$

$\underline{\underline{\bigstar{\textbf{\textsf{\green{\:Learn More\::-}}}}}}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}} \\ {\boxed{\boxed{\begin{array}{cc} \\ \dashrightarrow {\sf{Perimeter \: of \: Rectangle = 2(l+b)}} \\ \\ \: \: \dashrightarrow \sf{Diagonal \: of \: Rectangle = \sqrt{{l}^{2} + {b}^{2}}}\\ \\ \dashrightarrow \sf{Area \: of \: Rectangle = l \times b} \\ \\ \dashrightarrow \sf{Perimeter \: of \: square =4 \times a} \\ \\ \dashrightarrow \sf{Diagonal \: of \: square = \sqrt{2a}} \\ \\ \dashrightarrow \sf{ Area \: of \: square = {a}^{2} } \end{array}}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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