The length of a rectangle is 27 m longer than its breadth. If the perimeter of the rectangle is 110 m, then find its area
Answers
Answer:
574 m²
Step-by-step explanation:
Given: Length of the rectangle- 27 m longer than breadth, perimeter- 110 m, area- ?
Let 'b' be the breadth.
And let 'b+27' be the length.
Perimeter of a rectangle = 2 (l+b)
110 = 2 [(b+27)+b]
110/2 = (b+27)+b
55 = (b+27)+b
55-27 = 2b
28 = 2b
28/2 = b
14 m = b
Hence, the breadth is 14 m.
Length of the rectangle = breadth+27
= 14+27
= 41 m
Thus, the length is 41 m.
Area of a rectangle = l x b
= 41 x 14
= 574 m²
∴, area of the rectangle is 574 m².
Answer:
the area of the given rectangle is574 m²
Step-by-step explanation:
as per the given data in the question,
Length of the rectangle- 27 m longer than breadth, and the perimeter is given as 110 m,
here we need to find out the area:
Let 'b' be the breadth.
by the given condition,
And let 'b+27' be the length.
we know that ,
Perimeter of a rectangle = 2 (l+b)
110 = 2 [(b+27)+b]
110/2 = (b+27)+b
55 = (b+27)+b
55-27 = 2b
28 = 2b
28/2 = b
14 m = b
Hence, the breadth is 14 m.
Length of the rectangle = breadth+27
= 14+27
= 41 m
Thus, the length is 41 m.
Area of a rectangle = l x b
= 41 x 14
= 574 m²
∴, area of the rectangle is 574 m².
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