Question

The length of a rectangle is 3 1 6 cm longer than the width. The perimeter of the rectangle is 15 1 3 cm. What are the width and length of this rectangle?

Answer 1

Answer:

b=220.25,l=536.25

Step-by-step explanation:

let breadth=x, length=x+316

so,2(l+b)=1513

2(x+x+316)=1513

2(2x+316)=1513

4x+632=1513

4x=1513-632

x=881/4=220.25

220.25+316=536.25

Answer 2

The width and length of this rectangle are 3 $\frac{7}{12}$ cm and 4$\frac{1}{12}$ cm respectively.

Let the breadth of the rectangle be 'b'cm

Given, the length of the rectangle is 3/6 cm (=0.5 cm) longer than breadth.

So, length = (b + 0.5) cm

We know, perimeter of a rectangle is equal to 2(l+b), where l and b are the length and breadth of the rectangle.

So, perimeter = 2(b+0.5+b) = 2(2b + 0.5)cm.

Given, perimeter equals to 15 $\frac{1}{3}$ cm, which is 46/3 cm.

So, 2(2b + 0.5) = 46/3

⇒(2b + 0.5) = 23/3

⇒ 2b = 23/3 - 0.5 = 21.5/3

⇒ b = 21.5/6 = 43/12 = 3 $\frac{7}{12}$ cm.

This is the breadth.

Length = (b + 0.5)cm

= (43/12 + 0.5)cm = 49/12 cm = 4$\frac{1}{12}$ cm