Question

The length of a rectangle is 3 meters more than the width. The perimeter of the rectangle is 26 meters. If the width is b, which equation represents the situation? How many solutions will this equation have?

Answer 1

heya,
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Let the width be b meters
So, the length be 3+b meters

A.T.Q.

2(b+3+b) = 26
=> 2b+6+2b = 26
=> 4b = 26-6
=> 4b = 20
=> b = 20/4
=> b = 5

Therefore,

The width of rec.
= b meters
= 5 meters

The length of rec.
= 3+b meters
= 3+5 meters
= 8 meters

As,
Perimeter of rec.
= 2×(5+8) meters
= 2×13 meters
= 26 meters
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