The length of a rectangle is 30 cm more than its width.The perimeter of the rectangle is 292 cm.Find the length and width of the rectangle.
Answers
Answered by
4
Let the width be Xcm
Length = X + 30cm
Given,
2(l+b) = 292
l+b = 146
X +30 + X = 146
2X + 30 = 146
2X = 146-30
X = 116/2
= 58cm
Therefore the width is 58cm and the length is 88cm
Length = X + 30cm
Given,
2(l+b) = 292
l+b = 146
X +30 + X = 146
2X + 30 = 146
2X = 146-30
X = 116/2
= 58cm
Therefore the width is 58cm and the length is 88cm
Answered by
2
Step-by-step explanation:
Let the width be x
thus length 30 + x
Therefore perimeter = 2(l +b)
292= 2( 30 + x + x)
292/2 - 30 = 2x
(146 - 30)/2 = x
116/2 = x
x = 58 cm Thus width = 58cm length = 30 + 58 cm
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