the length of a rectangle is 3m greater than its width. determine its dimensions, if the perimeter of the rectangle is 26m.
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Answers
Answered by
4
let the width be x then length will be x+3
perimeter of rectangle = 2(l+b)
26= 2(x+x+3)
26=2(2x+3)
26/2 = 2x+3
13= 2x+3
13-3=2x
10=2x
10/2=x
5=x
so width= x=5
length = x+3=5+3=8
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Answered by
0
Answer:
13 cm and 16 cm
Step-by-step explanation:
Let the width be x and length be ( x + 3 ) .
now, we have,
P e r i m e t e r = 2 ( l + w )
58 c m = 2 ( x + x + 3 )
4 x + 6 = 58 c m
4 x = 52 c m
x = 52 /4 c m
∴ x = 13 c m
So, width =x =13 cm
and, length =x + 3 = 13 cm +3 =16 cm
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