Question

the length of a rectangle is 4 centimetre more than its breadth its perimeter is 56 cm find the length and the breadth with two variables.​

Answer 1

Answer:

length = 16 cm and breadth= 12 cm

Step-by-step explanation:

Let length=l and breadth= b.

Perimeter of a rectangle is 2(l+b).

Given that,

l=b+4

2(l+b)=56

(l+b)=28

b+4+b=28

2b+4=28

2b=28-4=24

therefore b= 24/2=12 cm

and l= b+4=12+4= 16cm

Answer 2

⋆ To Find :

• we need to find the length and breadth of rectangle.

⋆ Given :

• Length of rectangle is 4 cm more than it's breadth.
• perimeter of rectangle = 56cm

★ Solution :

• Let breadth of rectangle be x cm

So,

• Length of rectangle = x + 4

• Perimeter of rectangle = 56cm

we know that,

⇛Perimeter of rectangle = 2( l + b)

⇛2(x + x + 4) = 56

⇛2(2x + 4) = 56

⇛2x + 4 = 56/2

⇛2x + 4 = 28

⇛2x = 28 - 4

⇛2x = 24

⇛x = 24/2

⇛x = 12cm

So,

Breadth of rectangle x = 12cm

Length of rectangle x + 4 = 12 + 4 = 16cm

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⠀⠀⋆✫Some formulas :-

⪼ Area of rectangle = l × b

⪼ Perimeter of rectangle = 2(l + b)

⪼ Length of rectangle = Area/Breadth

⪼ Breadth of rectangle = Area/length

⪼ Diagonal of rectangle = √l² + b²

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