The length of a rectangle is 5 cm more than 3 times its width. The area of the rectangle is 1428 square cm. Find the length and width of the rectangle.
the answer is w=21 and l=68 but please show steps
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Answer:
Let 'L' be the length and 'W' be the width
L = 3W + 5
Area = 1428
length × width = 1428
(3W+5)W = 1428
3W^2 + 5W = 1428
using the formula -b±√b^2 - 4ac/2
we get w = 21 or -22.66
Width cannot be -ve. So W = 21
L = 3×21+5 = 68
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