Question

the length of a rectangle is 5 cm more than its breadth if the perimeter is 30 cm find the length and breadth of the triangle​

Answer 1

Answer:

Let the breadth of the rectangle be xcm

Then it's length=x+5cm

Perimeter=2(length+breadth)

⇒70=2(x+(x+5))

⇒

2

70

=2x+5

⇒2x+5=35

⇒2x=35−5=30

⇒x=

2

30

=15cm

Breadth=x=15cm and length=x+5=15+5=20cm

Answer 2

★GIVEN★

The length of a rectangle is 5 cm more than its breadth if the perimeter is 30 cm.

★To Find★

The length and breadth of the rectangle.

★SOLUTION★

• Let the breadth be x cm.
• Let the length be (x + 5) cm.
• Perimeter = 30 cm.

According to the question,

We know that,

$\large{\green{\underline{\boxed{\bf{Perimeter=2(Length+Breadth)}}}}}$

$\large\implies{\sf{30=2(x+5+x)}}$

$\large\implies{\sf{\dfrac{30}{2}=2x+5}}$

$\large\implies{\sf{15=2x+5}}$

$\large\implies{\sf{15-5=2x}}$

$\large\implies{\sf{10=2x}}$

$\large\implies{\sf{\dfrac{10}{2}=x}}$

$\large\implies{\sf{\dfrac{\cancel{10}}{\cancel{2}}=x}}$

$\large\implies{\sf{5=x}}$

$\large\therefore\boxed{\bf{x=5.}}$

The dimensions are:-

1. Length = x + 5 = 5 + 5 = 10 cm.
2. Breadth = x = 5 cm.

★VERIFICATION★

$\large\implies{\sf{30=2(10+5)}}$

$\large\implies{\sf{30=20+10}}$

$\large\implies{\sf{30=30}}$

$\large\therefore\boxed{\bf{LHS=RHS.}}$

Therefore,

The length and breadth of the rectangle is 10 cm and 5 cm respectively.