Question

The length of a rectangle is 5 more than its breadth and its perimeter is 62. Find its breadth.

Answer 1

let ( x ) units be the breadth of the rectangle.

Therefore, length = ( x + 5 ) units

thus,
A/Q,
$\qquad \tt \: perimeter = 2(length + breadth) \\ \\ \implies 62 = 2(x + 5 + x) \\ \\ \implies 62 = 2(2x + 5) \\ \\ \implies 62 = 4x + 20 \\ \\ \implies 4x = 62 - 20 \\ \\ \implies 4x = 42 \\ \\ \implies x = \frac{42}{4} = \frac{ \cancel{42} \: {}^{10.5} }{ \cancel{4} \: _1} \\ \\ \implies x = 10.5 \: \: \sf \: units$
Hence,
the breadth of the rectangle is ( 10.5 ) units.