Question

the length of a rectangle is 5cm less than twice its breadth.if the length is decreased by 3cm and breadth increased by 2cm, the perimeter of the resulting rectangle is72 cm. find the area of the original rectangle.

Answer 1

Let L & W be the original length and width
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Length of a rectangle is 5 cm less then twice its breadth,
L = 2W - 5
if the length is decreased by 3 cm and breadth increased by 2 cm the perimeter is 72.
2(L-3) + 2(W+2) = 72
Divide equation by 2
L - 3 + W + 2 = 36
L + W - 1 = 36
L + W = 37
Replace L with (2W-5)
(2W-5) + W = 37
3W = 37 + 5
3W = 42
W = 42/3
W = 14 cm is the original width
Find L
L = 2(14) - 5
L = 28 - 5
L = 23 cm is the original length
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 area of original rectangle.
23 * 14 = 322 sq cm
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Answer 2

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