Question

The length of a rectangle is 6 m more than its width. If each of the length and the breadth is increased by 4 m, the area is increased by 80sq. m. Find the dimensions of the original rectangle.​

Answer 1

Answer:

original dimension of the rectangle

length L=11 m width W = 5 m

after increase

length L=15 m width W = 9 m

Step-by-step explanation:

Answer 2

SOLUTION:-

Given:

•The length of a rectangle is 6m more than its width.

•If each of the length & the breadth is increased by 4m, the area is increased by 80m².

To find:

The dimensions of the original rectangle.

Explanation:

Let the original breadth of rectangle be R m.

&

Let the original length of rectangle be [R+6]m.

We know that, area of rectangle:

=) Length × Breadth

Therefore,

• Original area= (R+6) × R
• Original area= R² + 6R

Now,

New length of rectangle= [R+6] +4

New length of rectangle= R+10 m

&

New breadth of rectangle= R+4 m

Therefore,

New area of rectangle= (R+10)× (R+4)

New area of rectangle= R² + 4R+10R+40

New area of rectangle= R² + 14R +40

According to the question:

New area - Original area=80m²

=) (R² +14R +40) - (R² +6R)=80

=) R² +14R +40 - R² -6R=80

=) 14R -6R = 80 -40

=) 8R = 40

=) R = 40/8

=) R= 5m

So,

The original breadth of rectangle is R=5m.

The original Length of rectangle is R+6

=) (5 +6)m

=) 11m