Question

The length of a rectangle is 6 more than twice of breadth ,product of length and breadth 260 .If breadth is x then quadratic equation​

Answer 1

Answer:

HEY THERE!!

Question;-

Length of a rectangle is 6M more than twice its breadth if its perimeter is 66m find its length and breadth.

Method Of Solution;

Let to be Required breadth x

According to the Question;

*length of a rectangle is 6M less than twice its breadth*

=> 2x-6

Given: Perimeter of Rectangle

= 66

We know that formula of Perimeter of Rectangle= 2(l+b)

Substitute Required terms in Formula

2(L+b) =Perimeter

=> 2(2x-6+x)=66

=> 2(3x-6)=66

=> 3x-6=66/2

=> 3x-6=33

=> 3x=33+6

=> x=39/3

•°• x=13

Here, X is Equal as Breadth of Rectangle= 39 metre

Again, To find Length of Rectangle=?

Length =2x-6

Substitute the value of x in length to find it.

Length =2x-6

=2(13)-6

=26-6

=20

Hence,

Length of Rectangle=20 metre

Breadth of Rectangle=13 metre

Step-by-step explanation:

Answer 2

Answer:

b = $x$

l = 2b +6 = 2$x$ + 6             - (1)

lxb = 260                           - (2)      

put the value of b from equation 1 in equation 2

(2$x$ + 6) * $x$ = 260

$2x^{2} + 6x - 260 =0\\x^{2} +3x - 130 = 0$

$x^{2} + 13x- 10x - 130 = 0\\x(x + 13) - 10(x - 13 ) = 0\\(x-10) (x+13)=0\\x=10 ; x\neq -13\\l=2x+6=2*10+6= 20+6=26$