The length of a rectangle is 8 cm more than its width if the perimeter of the rectangle is 44 cm.Find the dimension of the triangle
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let the breadth be x
let the length be x+8
perimeter of rectangle=2 (length +breadth)
so, 2 (x+x+8)=44cm
=2 (2x+8)=44
=4x + 16=44
=4x= 44-16
=4x= 28
=x = 28÷4
=x= 7
therefore,
breadth is 7 (x)
length is 7+8 (x+8)
=15
let the length be x+8
perimeter of rectangle=2 (length +breadth)
so, 2 (x+x+8)=44cm
=2 (2x+8)=44
=4x + 16=44
=4x= 44-16
=4x= 28
=x = 28÷4
=x= 7
therefore,
breadth is 7 (x)
length is 7+8 (x+8)
=15
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