Question

The length of a rectangle is 8cm more than it's worth. If the perimeter of the rectangle is 64. Find its lengths and widths
ANSWER IS= WIDTH =12CM, LENGTH=20Cm
please give me answer solution by solution​

Answer 1

Given:-

• The length of a rectangle is 8cm more than it's breadth. If the perimeter of the rectangle is 64cm.

To Find:-

• Length ,l and Breadth ,b

Solution:-

Let the breadth of rectangle be x

So, the length of rectangle = x+8......(i)

And , we know that the perimeter of rectangle

• P = 2(l +b)

Substitute the value we get

→ 64 = 2(x + 8 +x)

→ 2 (x + 8 +x) = 64

→ x + 8 +x = 64/2

→ 2x + 8 = 32

→ 2x = 32-8

→ 2x = 24

→ x = 24/2

→ x = 12cm

Put the value of x in Equation (i) we get

→ x + 8 = 12+ 8 = 20

Therefore, the length of the rectangle is 20cm and the breadth of rectangle is 12 cm.

Answer 2

Solution

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Given,

• the length of a rectangle is 8 cm more than its breadth .
• the perimeter of the rectangle is 64 .

To find ,

• we have to find here its length and breadth .

We know that ;

to find the perimeter of rectangle ;

2( length + breadth )

now putting the value in the formula we get ;

$\bold{ = > 64 = 2(x + 8 + x)}$

$= > \frac{64}{2} = x + 8 + x$

$= > 32 = x + x + 8$

$= > 32 = 2x + 8$

$= > 32 - 8 = 2x$

$= > 24 = 2x$

$= > x = \frac{24}{2}$

$\bold{= > x = 12}$

So, the breadth is 12 cm .

Now ,

The length = "X+8" = "12+8" = 20 .

The length is 20cm and breadth is 12 cm .

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