Question

The length of a rectangle is greater than its breadth by 16 cm. If both
length and breadth are increased by 3 cm , then the area increases by
93 sq.cm. Find the length and breadth of the rectangle.

Answer 1

Answer:

Required Answer:-

1)The point under the ground where an earthquake begins.

Focus

The point above the point on the surface of earth is known as Epicenter and the places near it are the most affected.

2) The process of adding chlorine to water to kill germs.

Chlorination

This process is mainly used for the purification of water in large amount as well as in the home water filter..

3)The deep holes on the surface of the moon.

Craters

They are cracks formed by the hitting of meterioites and asteroids on the surface of moon.

4)The layer of the atmosphere in which spacecraft orbit.

Thermosphere & Exosphere.

Depends on the space shuttles, spacecrafts and the motive behind sending them to space.

5)The process by which salt can be separated from water.

Evaporation, then crystallization

Salt is a non-volatile solid which remains behind when water is evaporated. Later it is crystallized to get pure form of salt.

6)The types of tide in which the water level rises.

High tides.

They are due to the gravity of moon upon earth. The difference in height between the high tide and the low tide is called the tidal range.

Answer 2

Answer:

The original length of the rectangle is = 45 cm

The original breadth of the rectangle is = 29 cm

Step-by-step explanation:

Given :-

• Length of the rectangle greater than the breadth of the rectangle = 16 cm
• Increase in length and breadth = 3 cm
• Increase in Area = 93 cm²

To Find :-

• Original length and breadth of the rectangle

Formula Used :-

• Area of a rectangle Length × Breadth

Solution :-

Let the Breadth of the rectangle be 'a' cm,

∴ Length = (a + 16) cm

Area = (a + 16) cm × a cm = (a² + 16a) cm

New length = (a + 16 + 3)cm

New breadth = (a + 3) cm

New Area (with given increase) = (a² + 16a + 93) cm²

Finding value of a :-

$\longmapsto$ (a + 16 + 3) cm × (a + 3) cm = (a² + 16a + 93) cm²

$\longmapsto$ (a² + 3 + 19a + 3) cm² = (a² + 16a + 93) cm²

$\longmapsto$ (a² + 19a + 6) cm² = (a² + 16a + 93) cm²

$\longmapsto$ (19a + 6) cm² = ([a² - a²] + 16a + 93) cm²

$\longmapsto$ (19a + 6) cm² = (16a + 93) cm²        ... [∵ a² - a² = 0]

$\longmapsto$ 19a cm² = (16a + [93 - 6]) cm²

$\longmapsto$ 19a cm² = (16a + 87) cm²        ... [∵ 93 - 6 = 87]

$\longmapsto$ (19a - 16a) cm² = 87 cm²

$\longmapsto$ 3a cm² = 87 cm²

$\longmapsto$ a = ${\mathsf{\dfrac{87 \ cm^2}{3 \ cm^2}}}$

$\Longrightarrow {\mathsf{a = 29}}$

a = Breadth = 29 cm

Length = (29 + 16) cm = 45 cm

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