Question

the length of a rectangle is greater than its breadth by 3 if its area is 10 square metre find its perimeter​

Answer 1

Answer:

The Answer is 14 m.

Step-by-step explanation:

Suppose, the breadth of the rectangle =x m

Therefore, the length of the rectangle =(x+3) m

So, area = (x+3)x sq. m

Hence, by the condition of the problem,

x^2+3x=10

x^2 +3x−10=0

x^2 +5x−2x−10=0

x(x+5)−2(x+5)=0

(x+5)(x−2)=0

x=2,−5

Since, x cannot be negative. So, x=2.

Thus, l=5 m,b=2 m.

Hence, Perimeter =

2(l+b)=2(5+2)=14 m

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Answer 2

Answer:

Let the breadth of the rectangle =x m

Therefore, the length of the rectangle =(x+3) m

So, area = (x+3)x sq. m

Hence, by the condition of the problem,

x ^2+3x=10

x ^2 +3x−10=0

x^ 2 +5x−2x−10=0

x(x+5)−2(x+5)=0

(x+5)(x−2)=0

x=2,−5

Since, x cannot be negative. So, x=2.

Thus, l=5 m,b=2 m.

Hence, Perimeter = 2(l+b)=2(5+2)=14 m

Step-by-step explanation:

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