Question

The length of a rectangle is greater than the breadth by 3 cm if the lengthis increased by 9 cm. And breadth is reducedby 5 cm. The area remainsthe same find the dimensionsof the rectangle

Answer 1

Answer:

Let the breadth be x cm.

Let the breadth be x cm.Then the length will be (x+3) cm.

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we get

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we getx(x+3) = (x+12)(x-5)

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we getx(x+3) = (x+12)(x-5)x^2 + 3x = x^2 + 7x - 60

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we getx(x+3) = (x+12)(x-5)x^2 + 3x = x^2 + 7x - 604x = 60

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we getx(x+3) = (x+12)(x-5)x^2 + 3x = x^2 + 7x - 604x = 60x =  15.

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we getx(x+3) = (x+12)(x-5)x^2 + 3x = x^2 + 7x - 604x = 60x =  15.Breadth = 15cm.

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we getx(x+3) = (x+12)(x-5)x^2 + 3x = x^2 + 7x - 604x = 60x =  15.Breadth = 15cm.Length = 15 + 3 = 18 cm.

Let the breadth be x cm.Then the length will be (x+3) cm.Area of the rectangle = x(x+3) cm^2.   ---------------- (1)Given that length is increased by 9cm = x + 3 + 9 = x + 12 cm.Given that breadth is reduced by 5cm = x - 5 cm.Area of the rectangle = (x+12)(x-5).   -------------- (2)On solving (1) and (2), we getx(x+3) = (x+12)(x-5)x^2 + 3x = x^2 + 7x - 604x = 60x =  15.Breadth = 15cm.Length = 15 + 3 = 18 cm.