The length of a rectangle is increased by 10%.the breadth if a rectangle is increased by 20%.the perimeter of the rectangle is increased by x%.the range of x is?
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Let L = 10
Let W = 10 (a square is a rectangle)
Original area = (LW) = 10*10 = 100
L increases by 20 percent:
(1.2)(10) = 12
W decreases by 20 percent:
(0.8)(10) = 8
New area: (12)*(8) = 96
Percent change:\(\frac{New-Old}{Old} * 100\)
\(\frac{96-100}{100}=\)
\((-.04) * 100\) = 4 percent decrease
Algebra
L = length
W = width
Area = (1)LW
Length increases by 20 percent, width decreases by 20 percent:
1.2L * 0.8W = (.96) LW
.96 is 4 percent less than 1
The area decreases by 4 percent.
Let L = 10
Let W = 10 (a square is a rectangle)
Original area = (LW) = 10*10 = 100
L increases by 20 percent:
(1.2)(10) = 12
W decreases by 20 percent:
(0.8)(10) = 8
New area: (12)*(8) = 96
Percent change:\(\frac{New-Old}{Old} * 100\)
\(\frac{96-100}{100}=\)
\((-.04) * 100\) = 4 percent decrease
Algebra
L = length
W = width
Area = (1)LW
Length increases by 20 percent, width decreases by 20 percent:
1.2L * 0.8W = (.96) LW
.96 is 4 percent less than 1
The area decreases by 4 percent.
parulmaurya63pabcqb:
What is the range?
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