The length of a rectangle is increased by 50%.By what % shuold the width be decreased to maintain the same area?
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Answer:
33.33%
Step-by-step explanation:
L1 , W1 - Length * width of rectangle
L2 , W2 - Modified length & width of rectangle
L1 * W1 = L2 * W2
L2 = L1 * 1.5 ( 50 % increase )
L1 * W1 = L1 * 1.5 * W2
W2 = W1/1.5
W2 = W1 *2/3
Width decrased by W1-W2 = W1 - W12/3 = 1/3 W1
So 33.33% reduction
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