The length of a rectangle is increased by 60% and its width remains the same. what is the ratio of the new area to the old area of the rectangle?select one:
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Let the initial length be “ l ”
Initial Breadth be “ b
Now, Area = lb
Given length is increased by 60% = l+60% of l =l +3/5 l =8/5 l
Now area = 8/5 l * b = 8/5 lb
Ratio of Areas = lb: 8/5 lb = 1:8/5 =5:8.
the ratio of the new area to the old area of the rectangle is 5:8.
Initial Breadth be “ b
Now, Area = lb
Given length is increased by 60% = l+60% of l =l +3/5 l =8/5 l
Now area = 8/5 l * b = 8/5 lb
Ratio of Areas = lb: 8/5 lb = 1:8/5 =5:8.
the ratio of the new area to the old area of the rectangle is 5:8.
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