The perimeter of a right triangle is 40 cm and the hypotenuse is 17 cm find the area
jsdcorreo:
60 cm² -- http://triancal.esy.es/?g=3&c=17&p=40
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Let x + y + z = 40 cm
x + y = 40 - z = 23 cm
x = 23 - y
and x2 + y2 = z2
(23 - y)2 + y2 = 172
529 - 46y + y2 + y2 = 289
2y2 - 46y + 240 = 0
2y2 - 46y + 240 = 0
y = [46 ± ( 2116 - 1920)]/4
y = [46 ± 14]/4 = 15 or 8
x = 8 or 15,
s = semiperiemeter = 40/2 = 20
A = (s(s-x)(s-y)(s-z))1/2 = (20(12)(5)(3))1/2
= 60 cm2
x + y = 40 - z = 23 cm
x = 23 - y
and x2 + y2 = z2
(23 - y)2 + y2 = 172
529 - 46y + y2 + y2 = 289
2y2 - 46y + 240 = 0
2y2 - 46y + 240 = 0
y = [46 ± ( 2116 - 1920)]/4
y = [46 ± 14]/4 = 15 or 8
x = 8 or 15,
s = semiperiemeter = 40/2 = 20
A = (s(s-x)(s-y)(s-z))1/2 = (20(12)(5)(3))1/2
= 60 cm2
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The other two sides of a right angle triangle will not be same
yes it is ,now it's correct
area=60
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Answer:
60 cm
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