Question

The length of a rectangle is less than twice its breadth by 1 cm. The length of its diagonal is
17 cm. Find its length and breadth. (Quadratic)
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Answer 1

Answer:

breadth=10,length=19

Step-by-step explanation:

let breadth=b and length=l

2b-l=1 => l=2b-1

$l^{2} +b^{2} =17*17$

$(2b-1)^{2}$+$b^{2}$=289

hence b=10cm ( by using shri dharacharya formula)

l=2b-1

=2*10-1

=19

hence b=10cm,l=19cm

Answer 2

Here's the answer for your question in the above attachment

Step-by-step explanation:

I Hope this helps you