Math, asked by paru59, 1 year ago

The length of a rectangle is sixteen cm and the length of its diagonal is twenty cm . The area of the rectangle is

Answers

Answered by BrAinlyPriNcee

Que:- The length of a rectangle is sixteen cm and the length of its diagonal is twenty cm . The area of the rectangle is ?

Solution:-

Length = 16 cm.
Diagonal = 20 cm.

By Pythagoras theorem,

Diagonal ^2 = Length ^2 + Breadth ^2

=> 20^2 - 16^2 = Breadth
=> Breadth^2 = 400 - 256
=> Breadth^2 = 144
=> Breadth = 12 cm.

Now, Area of Rectangle = Length × Breadth
=> 16 × 12
=> 192 cm^2.

Attachments:

dorri: Question was asked for area of Rectangle, not triangle...

BrAinlyPriNcee: Okay.. Corrected✔✔

Answered by dorri

Length of Rectangle = 16cm
Diagonal =20cm

By Pythagoras Theorem
Diagonal²=Breadth²+Length²
20²=B²+16²
20²-16²=B²
400-256=B²
B=√144
B= 12

Area of Rectangle = l×b = 16×12 = 192cm²

paru59: your Pythagoras theoram is outdated

paru59: try some new

paru59: do you herons fomulae

paru59: search it on google

dorri: Yah i know Heron's formula it's √S(S-A)(S-B)(S-C), where A, B, C are the sides of triangle. But we can't use it in this question.

dorri: Because S is Sum of all sides/2 i.e ½ perimeter, but we don't have 1 the side so we also can't find the S

dorri: You just simply can't say that if a formula is outdated you would not use it.... We should know when to use which formula

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