Question

The length of a rectangle is three more than twice its width. If the perimeter of the rectangle is 60 cm. Find its length and width.

Answer 1

Given: The length of a rectangle is three more than twice its width and the perimeter of the rectangle is $60$cm.

We have to find the length and width of the rectangle.

We are solving in the following way:

Let the length of the rectangle be $L$and width be$W$.

So, from the given statement we can write:

$\begin{array}{l}L=2 W+3 \\\end{array}$

As we know that the perimeter of a rectangle is calculated by:

$P=2(L+W)$

So,

$=>P=2(L+W)\\=>60 =2(L+W)\\=>60 / 2=L+W\\=>L+W=30$

We have,

$\begin{array}{l}L=2 W+3 \\\end{array}$

$L+W=30$

By putting the value of $L$in the equation$L+W=30$.

$=>L+W=30\\=>2W+3+W=30\\=>3W+3=30\\=>3W=30-3\\=>3W=27\\=>W=\frac{27}{3}$

Solving the above equation further we get,

$W=9$

Now,

$=>L+W=30\\=>L+9=30\\=>L=30-9\\=>L=21$

Hence, the length and width of the rectangle are $21$and$9$ feet.