Math, asked by katika, 10 months ago

The length of a rectangle is three times its breadth. The
breadth is half the side of a square whose perimeter is
72 cm. Then,
(1) the perimeters of both rectangle and square are equal
(2) the perimeter of the rectangle is less than the perimeter of
the square
(3) the areas of the square and rectangle are equal
(4) the area of the rectangle is more than the area of the square​

Answers

Answered by Anonymous0505
0

Answer:

Step-by-step explanation:

Since l is three times the b

l=3b and let a be the side of the square

b=1/2a

Perimeter of rectangle= 2(l+b)

=2(3b+b) =2(4b)=8b

=8×1/2a=4a

We already know perimeter of square is 4a.

So, 4a=4a

So both the perimeters will be equal.

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