Question

The length of a rectangle is three times its width. The perimeter is at most 112 centimeters What is the greatest possible value for the width?

Answer 1

let b=x

so l=3x

p=112 (given)

p=2(l +b)

then put the value

112=2(3x+x)

112 divided by 2= 3x+x

56= 4x

56 divided by 4= x

14 = x =b