The length of a rectangle is three times of its width. If the length of the diagonal is
then the perimeters of rectangle is
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Answer:
Perimeter = 64 m
Step-by-step explanation:
Let the Breadth be x,
So, Length = 3x
we are given Diagonal = 8√10 m
We also know that,
Each angle in a rectangle is 90° and forms a right triangle when a diagonal is drawn.
Thus,
By Pythagoras theorem,
Length² + Breadth² = Diangonal²
(3x)² + x² = (8√10)²
3²x² + x² = 8²(√10)²
9x² + x² = 64 × 10
10x² = 640
x² = 640/10
x² = 64
x = √64
x = 8 m
We are not considering the-ve value because it is a rectangle, and its sides can't be negative.
So,
Length = 3 × 8
Length = 24 m
Breadth = 8 m
Now,
Perimeter of a rectangle = 2(L + B)
P = 2(24 + 8)
P = 2 × 32
P = 64 m
Hence, the Perimeter is 64 m
Hope it helped and believing you understood it........All the best.
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