Question

the length of a rectangle is twice its breadth if the perimeter of a right triangle is 60 cm find the dimension of rectangle

Answer 1

Correct question

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The length of a rectangle is twice its breadth if the perimeter of a rectangle is 60 cm find the dimension of rectangle

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$\underline{\underline{\huge{\gray{\tt{\textbf Answer :-}}}}}$

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$\sf\large\bold{\orange{\underline{\blue{ Given :-}}}}$

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• The length of a rectangle is twice its breadth

• Perimeter of a rectangle is 60 cm

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$\sf\large\bold{\orange{\underline{\blue{ To \: Find :-}}}}$

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• Dimensions of rectangle

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$\sf\large\bold{\orange{\underline{\blue{ Solution :-}}}}$

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Let the breadth of rectangle be "a"

Thus the length of rectangle will be "2a"

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$\underline{\bold{\texttt{Perimeter of rectangle :}}}$

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➠ P = 2(L + B) ⚊⚊⚊⚊ ⓵

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Where ,

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• P = Perimeter

• L = Length

• B = Breadth

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$\underline{\bold{\texttt{Perimeter of given rectangle :}}}$

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• P = 60

• L = 2a

• B = a

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⟮ Putting the above values in ⓵ ⟯

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➜ P = 2(L + B)

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➜ 60 = 2(2a + a)

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➜ 60 = 2(3a)

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➜ 60 = 6a

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➜ $\sf a = \dfrac { 60 } { 6 }$

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➨ a = 10

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• Hence the breadth of rectangle is 10 cm

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➨ Length = 2a = 20

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• Hence the length of rectangle is 2(10) = 20 cm

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∴ The length and breadth of rectangle are 20 cm & 10 cm respectively