Question

the length of a rectangle is twice to its breadth.if the perimeter is 72.6cm then find the length and the breadth​

Answer 1

Answer:

length = 24.2 cm , breadth = 12.1 cm .

Step-by-step explanation:

let the breadth of rectangle be "x".

From statement first length is twice of breadth that means length of rectangle is "2x".

Perimeter of rectangle = 2(l + b)

72.6 = 2(2x + x)

72.6 = 2(3x)

72.6 = 6x

72.6 ÷ 6 = x

12.1 = x

Value of "x" is 12.1 .

Breadth of rectangle is "x" = 12.1 cm

that means breadth is 12.1 cm

Length of rectangle is "2x" = 2 × 12.1 cm

= 24.2 cm

Length of rectangle is 24.2 cm.

l = 24.2 cm

b = 12.1 cm .

Answer 2

Correct Question-:

• The length of a rectangle is twice to its breadth.if the perimeter is 72.6cm then, find the length and the breadth.

AnswEr -:

• $\boxed{\purple{\sf{\star{The\:length \:and\:breadth\:of\:Rectangle\:are\:24.2cm\:and\:12.1cm.}}}}$

Explanation-:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 24.2cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 12.1cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Given,

• The length of a rectangle is twice to its breadth.
• The perimeter Rectangle is 72.6cm .

To Find,

• The length and breadth of Rectangle.

Solution-:

• Let the breadth of Rectangle be X cm. .........[1]

Then ,

According to the question ❓,

• The length of a rectangle is twice to its breadth = 2 × x = 2x cm . ...........[2]

• $\boxed{\blue{\sf{\star{Perimeter\:of\:Rectangle\:=\: 2(length+breadth)}}}}$

Here ,

• Length of Rectangle is 2x cm . ...........[ From 2]
• Breadth of Rectangle is x cm . ...........[ From 1]

Now ,

• $\pink{\sf{\implies { 72.6\:cm\:=2(x + 2x)}}}$
• $\pink{\sf{\implies { \frac{72.6}{2}\:=(x + 2x)}}}$
• $\pink{\sf{\implies { 72.6\:cm\:=2(x + 2x)}}}$
• $\pink{\sf{\implies { 36.3\:\:=x + 2x}}}$
• $\pink{\sf{\implies { 36.3\:\:=3x}}}$
• $\pink{\sf{\implies { x\:=\frac{36.3}{3}}}}$
• $\pink{\sf{\implies { x\:=12.1}}}$

Therefore,

• $\boxed{\purple{\sf{\implies { x\:=12.1}}}}$

Now ,

• The length of Rectangle is 2x = 2 × 12.1 = 24.2 cm
• The breadth of Rectangle is x = 12.1 cm

Hence,

• $\boxed{\purple{\sf{\star{The\:length \:and\:breadth\:of\:Rectangle\:are\:24.2cm\:and\:12.1cm.}}}}$

______________________________________________________

♤| Verification |♤

• $\boxed{\blue{\sf{\star{Perimeter\:of\:Rectangle\:=\: 2(length+breadth)}}}}$

Here ,

• The length of Rectangle is = 24.2 cm
• The breadth of Rectangle is = 12.1 cm

Now ,

• $\pink{\sf{\implies { 72.6\:cm\:=2(12.1 + 24.2)}}}$
• $\pink{\sf{\implies { 72.6\:cm\:=2(36.3)}}}$
• $\pink{\sf{\implies { 72.6\:cm\:=72.6 cm}}}$

$\boxed{\purple{\sf{\star{Therefore ,\:LHS \:=\:RHS\:.}}}}$

$\boxed{\green{\sf{\star{Hence ,\:Verified \:\:!!\:.}}}}$

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