Question

the length of a rectangle is two times its width. if the perimeter is 60m,find the length of the rectangle ​

Answer 1

Answer:

10

Step-by-step explanation:

2(2X)+2(X)=60

4X+2X=60

6X=60 now we divide each side by 6.

6X/6=60/6

X=10 now lets prove X=10

2(2X)+2(X)=60

2(2×10)+2(10)=60

2(20)+2(10)=60

40+20=60

60=60

so X is equal to 10.

Answer 2

☆ GiveN :

• The Length of rectangle is two times its width
• The perimeter of rectangle is 60 m

☆ To finD :

• The length of the rectangle.

☆ SolutioN :

Let's assume the width of the rectangle as x

Then the length will be 2(x) = 2x

★ Perimeter (rectangle) = 2(length + breadth)

[Width can be also called as Breadth]

A/Q

➙ 60 = 2( 2x + x )

➙ 60 = 2(3x)

➙ 60 = 2 × 3x

➙ 60 = 6x

➙ 60/6 = x

➙ 10 = x

➙ x = 10

Therefore,

The width of the rectangle (x) is 10 m

Hence,

The length will be 2 × 10 = 20 m respectively.

Check :

As we know,

Perimeter of rectangle = 2(l+b)

Thus,

→ 60 = 2( 20 + 10 )

→ 60 = 2 (30)

→ 60 = 2 × 30

→ 60 = 60

∴ We have both sides equal values.

Thus, checked !!