the length of a rectangle is two times its width. if the perimeter is 60m,find the length of the rectangle
Answers
Answered by
0
Answer:
10
Step-by-step explanation:
2(2X)+2(X)=60
4X+2X=60
6X=60 now we divide each side by 6.
6X/6=60/6
X=10 now lets prove X=10
2(2X)+2(X)=60
2(2×10)+2(10)=60
2(20)+2(10)=60
40+20=60
60=60
so X is equal to 10.
Answered by
44
☆ GiveN :
- The Length of rectangle is two times its width
- The perimeter of rectangle is 60 m
☆ To finD :
- The length of the rectangle.
☆ SolutioN :
Let's assume the width of the rectangle as x
Then the length will be 2(x) = 2x
★ Perimeter (rectangle) = 2(length + breadth)
[Width can be also called as Breadth]
A/Q
➙ 60 = 2( 2x + x )
➙ 60 = 2(3x)
➙ 60 = 2 × 3x
➙ 60 = 6x
➙ 60/6 = x
➙ 10 = x
➙ x = 10
Therefore,
The width of the rectangle (x) is 10 m
Hence,
The length will be 2 × 10 = 20 m respectively.
Check :
As we know,
Perimeter of rectangle = 2(l+b)
Thus,
→ 60 = 2( 20 + 10 )
→ 60 = 2 (30)
→ 60 = 2 × 30
→ 60 = 60
∴ We have both sides equal values.
Thus, checked !!
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