Question

the length of a rectangle shaped park exceeds it's breadth by 17m the perimeter of the park is 178 m if the breadth of the park is x then find
the length of the park in terms of x
the length and breadth of the park in meters
the area of the park
with clear explanation with formulas
​

Answer 1

Answer:

Step-by-step explanation:

Let the breadth of the park be =x meters

Then the length of the park =x+17 meters

∴ perimeter of the park =2(length+breadth)

=2(x+17+x) meters

=2(2x+17) meters

But it is given that the perimeter of the rectangle is 178 meters

∴ 2(2x+17)=178

4x+34=178

4x=178−34

4x=144

x=  144/4

​  

=36

Therefore the breadth of the park =36 meters

Length of the park =36+17=53 meters.

Answer 2

Let the breadth of the park be =x meters

Then the length of the park =x+17 meters

∴ perimeter of the park =2(length+breadth)

=2(x+17+x) meters

=2(2x+17) meters

But it is given that the perimeter of the rectangle is 178 meters

∴ 2(2x+17)=178

4x+34=178

4x=178−34

4x=144

x=  144/4

 

=36

Therefore the breadth of the park =36 meters

Length of the park =36+17=53 meters.