Question

The length of a rectangular deck is 4 times its width. if the deck's perimeter is 30 feet, what is the deck's area?

Answer 1

Answer:

Step-by-step explanation:

Let width be x

Then, length be 4x

Perimeter=2(l+b)

30=2(4x+x)

30=2×5x

30=10x

x=3feet

Length=4×3=12 feet

Width=3 feet

Area=lb

=12×3=36 feet^2

Answer 2

The correct answer is 36 sq. feet.

Given: Length = 4*Width.

Perimeter = 30 feet.

To Find: Area of deck.

Solution:

Perimeter = 2(l + b)

Here, l = 4*b   (equation 1)

30 = 2(4b + b)

15 = 5b

b = 3 feet

Put in equation 1.

l = 4b

l = 4*3

l = 12 feet

Area of rectangle = l*b

= 3*12

= 36 sq. feet

Hence, the area of deck is 36 sq. feet.

#SPJ3