Question

the length of a rectangular feild is twice of breath .if the perimeter of the feild is 228 meter .find the dimensions of the feild

Answer 1

here you go ☆☆

let-

▪breadth = x
▪length = 2x

perimeter of rectangle = 228

2( l + b ) = 228

2( x + 2x ) = 228

6x = 228

x = 228/6

x = 38

so,

□breadth = 38m
□length = 38 × 2 => 76m

$<marquee> hope it helps you✌✌$

Answer 2

let the breadth be X
Length will be 2X
as we know
perimeter of rectangle =2 (l+b)
228=2 (x+2x)
228=2x+4x
228=6x
38=X=breadth
length =2x
=2×6=18