The length of a rectangular field exceeds its breadth by 5
m.if the perimeter of the field is 142m, find the dimensions of the field.
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Given information :
✴The length of the rectangular field exceeds the breadth by 5 m.
✴The perimeter of the field is 142 m .
Solution :
Let the breadth of the rectangular field be 'b'
According to the given information , the length(l) is (b+5)
Perimeter of the rectangular field =142 m
Perimeter of rectangle = 2(l+b)
2(b+5+b) = 142 m
2(2b+5) = 142
2b+5 =142/2
2b + 5 = 71
2b = 71-5
2b = 66
b= 66/2
b= 33
Breadth (b) = 33m
Length (l) = b +5 = 33+5 = 38 m
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