Question

the length of a rectangular field is 8 meter less than twice it's breadth if the perimeter of a rectangular field is 56 meters,find it's length and breadth ​

Answer 1

Given :-

• The length of a rectangular field is 8 meter less than twice it's breadth if the perimeter of a rectangular field is 56 meters.

To find :-

• Length and breadth of rectangle

Solution :-

Let the breadth be x

• The length of a rectangular field is 8 meter less than twice it's breadth.

• Breadth = 2x - 8

→ Perimeter of rectangle = 2(l + b)

Where " l " is length and " b " is breadth of a rectangle.

According to question

→ Perimeter of rectangle = 56

→ 2(l + b) = 56

→ 2[(2x - 8) + x] = 56

→ 2x - 8 + x = 56/2

→ 3x - 8 = 28

→ 3x = 28 + 8

→ 3x = 36

→ x = 36/3

→ x = 12

Hence,

• Breadth of rectangle = x = 12 m

• Length of rectangle = 2x - 8 = 2*12 - 8 = 24 - 8 = 16 m

Verification :-

• Perimeter of rectangle = 56

→ 2(l + b) = 56

→ 2(16 + 12) = 56

→ 2 × 28 = 56

→ 56 = 56

• Hence verified

Answer 2

Given:-

• let the breadth of rectangle(b) = x m
• then length() = (2x-8) m

SOLUTION:-

• perimeter of rectangle = 56 m

• 2+b) = 56

• 2(2x-8+x)= 56

• 3x-8 28

• 3x =28+8

• X = 36/3 = 12 m

• therefore length() 2x-8-212-8=16 meters

• breadth(b) = x = 12 meters